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.03x^2-5x+900=730
We move all terms to the left:
.03x^2-5x+900-(730)=0
We add all the numbers together, and all the variables
.03x^2-5x+170=0
a = .03; b = -5; c = +170;
Δ = b2-4ac
Δ = -52-4·.03·170
Δ = 4.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{4.6}}{2*.03}=\frac{5-\sqrt{4.6}}{0.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{4.6}}{2*.03}=\frac{5+\sqrt{4.6}}{0.06} $
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